With solar the Australian and New Zealand standards stipulate a max of 2% voltage rise from the POS/POA all the way through to the inverter with the largest run and/or biggest load current.
AS4777 uses the millivolt per A.M method which assumes almost the worst case scenario but there are other methods to calculate Voltage rise and in this presentation we will compare the ‘standard’ method with the cable impedance method.
In AS/NZS 4777.1 Volt rise is restricted to 2%
This is from Point of Supply to last inverter and the Distributor requires this information
The installer must assess the existing cable, do the necessary calculations and this determines new cabling specs.
Our example solar system consists of the following:
The cables are installed in the following manner:
AS/NZS 4777.1 references a table in AS/NZ 3008
This reference is Table 41, column 6
So the calculation is Vd/r* = L x I x Vc/1000 where:
In our example we have 3 x 100 kVA inverters cable to a PVDB to a DB to MSB to the POS.
We are talking about volt rise here but cables also have to be selected on the CCC ( current carrying capacity ) as well.
In our example some parallel cables have been used. In this case the current is equally distributed between the parallel cables and this is reflected in the Vrise result.
So what are the results?
Resulting in a total Vrise of 1.918% for the total run
According to AS3008: 2017 “A more accurate assessment can be made of the actual voltage drop (Vd) using the appropriate equation of Clause 4.5, the cable reactance determined from Table 30 to 33, the cable a.c. resistance determined from Table 34 to 39”
The calculation is as follows:
Vd = IZc . . . 4.3(1) where:
Where:
Single-phase, two-wire supply system
For a single-phase circuit the impedance of the active and neutral conductors is taken into account. As these conductors are of the same material and generally the same size, the voltage drop on the circuit is twice what it would be for a single cable:
Vd=ILZc/1000
For a balanced three-phase circuit no current is flowing in the neutral conductor and at any given instant the current flowing in one active conductor will be balanced by the currents flowing in the other active conductors. The voltage drop per phase to neutral is the voltage drop in one cable and the voltage drop between phases is:
Vd=√3ILZc/1000
It can be seen from the two methods outlined that the cable impedance method of determining the Voltage rise gives a lower figure. In most cases use the mV/A.m method will suffice BUT if the result is slightly over 2% then using another more accurate method may be the way to go.
Remember not only does the cable have to satisfy all Vrise stipulations but also it has to be able to safely carry the current that the system imposes on it.
Good luck on your next project.
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