How much do you use?
A common question with larger roof and ground mount systems is how much cable is required and calculations need to be made in order to cost the job correctly. In this article we look at DC cable, how much, what kind etc.
The assumptions:
In addition looking at:
Per row there are 8 x strings of 20 x 400 watt panels per string so row length is approximately 85 metres wide.
There are 20 rows, total distance, North South with spacing is 142 metres which includes the 4 metre North and 4 metre South perimeter roads.
Where a system is located and the pitch of the array both play a role in regards to panel row spacing and hence DC cable runs.
In this case we are assuming:
First we determine the overall width of the row and in this case it is approximately 85 metres made up of 80 panels per tier and there are 2 x tiers.
In this case the combined length of the positive and negative cables per row is approximately 256 metres
Made up of:
Each string’s horizontal distance has been calculated at 10.65 metres. The string is across two tiers, 10 panels per tier and takes into account the panel width and the gaps between the individual panels.
First row uses 256 metres of cabling
From the centre of each row there is a cable run that travels all the way to the inverter station that is situated behind the last row.
As there are no parallel strings and there are 8 x strings per row this means that there are 16 x DC cable runs per row back to the inverters.
In regards to the row furthest away from the inverters ( we will call this row 1) the distance is 133 metres* and this calculation was made using:
*North South distance of 8 metres subtracted
DC cable on a ground mount system
As we progress closer to the inverter station row by row the total distance reduces by the distance between the panels, centre to centre by a certain factor, in this case it is approximately 7 metres ( distance between the poles)
So in the case of the next row, row 2 the calculation is 16 x (133 -7) = 2016 metres.
Effectively we subtract the distance between the panels using the pole positions for each row then multiply this distance by the number of cables.
As the inverters are positioned on the back of the last row this run is negligible. In this scenario I have assumed 1 metre to inverters so the last row run is 16 x 1 = 16 metres.
Large solar projects, both ground mount and roof mount require a considerable amount of DC cable so there is definitely a need for a process and procedure that allows accurate calculations of these runs. This is part one of a three part series.
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